Optimal. Leaf size=47 \[ \frac {\tanh ^{-1}\left (\frac {f x}{e}\right ) (a-b \log (2))}{e f}+\frac {b \text {Li}_2\left (1-\frac {2 e}{e+f x}\right )}{2 e f} \]
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Rubi [A]
time = 0.04, antiderivative size = 47, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 4, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.138, Rules used = {2450, 214,
2449, 2352} \begin {gather*} \frac {b \text {PolyLog}\left (2,1-\frac {2 e}{e+f x}\right )}{2 e f}+\frac {(a-b \log (2)) \tanh ^{-1}\left (\frac {f x}{e}\right )}{e f} \end {gather*}
Antiderivative was successfully verified.
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Rule 214
Rule 2352
Rule 2449
Rule 2450
Rubi steps
\begin {align*} \int \frac {a+b \log \left (\frac {e}{e+f x}\right )}{e^2-f^2 x^2} \, dx &=b \int \frac {\log \left (\frac {2 e}{e+f x}\right )}{e^2-f^2 x^2} \, dx+(a-b \log (2)) \int \frac {1}{e^2-f^2 x^2} \, dx\\ &=\frac {\tanh ^{-1}\left (\frac {f x}{e}\right ) (a-b \log (2))}{e f}+\frac {b \text {Subst}\left (\int \frac {\log (2 e x)}{1-2 e x} \, dx,x,\frac {1}{e+f x}\right )}{f}\\ &=\frac {\tanh ^{-1}\left (\frac {f x}{e}\right ) (a-b \log (2))}{e f}+\frac {b \text {Li}_2\left (1-\frac {2 e}{e+f x}\right )}{2 e f}\\ \end {align*}
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Mathematica [A]
time = 0.02, size = 80, normalized size = 1.70 \begin {gather*} \frac {-\left (\left (a+b \log \left (\frac {e}{e+f x}\right )\right ) \left (a+2 b \log \left (\frac {e-f x}{2 e}\right )+b \log \left (\frac {e}{e+f x}\right )\right )\right )+2 b^2 \text {Li}_2\left (\frac {e+f x}{2 e}\right )}{4 b e f} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(102\) vs.
\(2(45)=90\).
time = 0.74, size = 103, normalized size = 2.19
method | result | size |
derivativedivides | \(-\frac {e \left (\frac {a \ln \left (\frac {2 e}{f x +e}-1\right )}{2 e^{2}}-\frac {b \ln \left (1-\frac {2 e}{f x +e}\right ) \ln \left (\frac {2 e}{f x +e}\right )}{2 e^{2}}+\frac {b \ln \left (1-\frac {2 e}{f x +e}\right ) \ln \left (\frac {e}{f x +e}\right )}{2 e^{2}}-\frac {b \dilog \left (\frac {2 e}{f x +e}\right )}{2 e^{2}}\right )}{f}\) | \(103\) |
default | \(-\frac {e \left (\frac {a \ln \left (\frac {2 e}{f x +e}-1\right )}{2 e^{2}}-\frac {b \ln \left (1-\frac {2 e}{f x +e}\right ) \ln \left (\frac {2 e}{f x +e}\right )}{2 e^{2}}+\frac {b \ln \left (1-\frac {2 e}{f x +e}\right ) \ln \left (\frac {e}{f x +e}\right )}{2 e^{2}}-\frac {b \dilog \left (\frac {2 e}{f x +e}\right )}{2 e^{2}}\right )}{f}\) | \(103\) |
risch | \(-\frac {a \ln \left (f x -e \right )}{2 e f}+\frac {a \ln \left (f x +e \right )}{2 e f}+\frac {b \ln \left (1-\frac {2 e}{f x +e}\right ) \ln \left (\frac {2 e}{f x +e}\right )}{2 e f}-\frac {b \ln \left (1-\frac {2 e}{f x +e}\right ) \ln \left (\frac {e}{f x +e}\right )}{2 e f}+\frac {b \dilog \left (\frac {2 e}{f x +e}\right )}{2 f e}\) | \(119\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - \int \frac {a}{- e^{2} + f^{2} x^{2}}\, dx - \int \frac {b \log {\left (\frac {e}{e + f x} \right )}}{- e^{2} + f^{2} x^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {a+b\,\ln \left (\frac {e}{e+f\,x}\right )}{e^2-f^2\,x^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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